Most Common Word

// Accepted solution for LeetCode #819: Most Common Word
import java.util.regex.Matcher;
import java.util.regex.Pattern;

class Solution {
    private static Pattern pattern = Pattern.compile("[a-z]+");

    public String mostCommonWord(String paragraph, String[] banned) {
        Set<String> bannedWords = new HashSet<>();
        for (String word : banned) {
            bannedWords.add(word);
        }
        Map<String, Integer> counter = new HashMap<>();
        Matcher matcher = pattern.matcher(paragraph.toLowerCase());
        while (matcher.find()) {
            String word = matcher.group();
            if (bannedWords.contains(word)) {
                continue;
            }
            counter.put(word, counter.getOrDefault(word, 0) + 1);
        }
        int max = Integer.MIN_VALUE;
        String ans = null;
        for (Map.Entry<String, Integer> entry : counter.entrySet()) {
            if (entry.getValue() > max) {
                max = entry.getValue();
                ans = entry.getKey();
            }
        }
        return ans;
    }
}

// Accepted solution for LeetCode #819: Most Common Word
func mostCommonWord(paragraph string, banned []string) string {
	s := make(map[string]bool)
	for _, w := range banned {
		s[w] = true
	}
	counter := make(map[string]int)
	var ans string
	for i, mx, n := 0, 0, len(paragraph); i < n; {
		if !unicode.IsLetter(rune(paragraph[i])) {
			i++
			continue
		}
		j := i
		var word []byte
		for j < n && unicode.IsLetter(rune(paragraph[j])) {
			word = append(word, byte(unicode.ToLower(rune(paragraph[j]))))
			j++
		}
		i = j + 1
		t := string(word)
		if s[t] {
			continue
		}
		counter[t]++
		if counter[t] > mx {
			ans = t
			mx = counter[t]
		}
	}
	return ans
}

# Accepted solution for LeetCode #819: Most Common Word
class Solution:
    def mostCommonWord(self, paragraph: str, banned: List[str]) -> str:
        s = set(banned)
        p = Counter(re.findall('[a-z]+', paragraph.lower()))
        return next(word for word, _ in p.most_common() if word not in s)

// Accepted solution for LeetCode #819: Most Common Word
use std::collections::{HashMap, HashSet};
impl Solution {
    pub fn most_common_word(mut paragraph: String, banned: Vec<String>) -> String {
        paragraph.make_ascii_lowercase();
        let banned: HashSet<&str> = banned.iter().map(String::as_str).collect();
        let mut map = HashMap::new();
        for word in paragraph.split(|c| !matches!(c, 'a'..='z')) {
            if word.is_empty() || banned.contains(word) {
                continue;
            }
            let val = map.get(&word).unwrap_or(&0) + 1;
            map.insert(word, val);
        }
        map.into_iter()
            .max_by_key(|&(_, v)| v)
            .unwrap()
            .0
            .to_string()
    }
}

// Accepted solution for LeetCode #819: Most Common Word
function mostCommonWord(paragraph: string, banned: string[]): string {
    const s = paragraph.toLocaleLowerCase();
    const map = new Map<string, number>();
    const set = new Set<string>(banned);
    for (const word of s.split(/[^A-z]/)) {
        if (word === '' || set.has(word)) {
            continue;
        }
        map.set(word, (map.get(word) ?? 0) + 1);
    }
    return [...map.entries()].reduce((r, v) => (v[1] > r[1] ? v : r), ['', 0])[0];
}