Off-by-one on range boundaries
Wrong move: Loop endpoints miss first/last candidate.
Usually fails on: Fails on minimal arrays and exact-boundary answers.
Fix: Re-derive loops from inclusive/exclusive ranges before coding.
Build confidence with an intuition-first walkthrough focused on core interview patterns fundamentals.
DataFramedf1+-------------+--------+ | Column Name | Type | +-------------+--------+ | student_id | int | | name | object | | age | int | +-------------+--------+ DataFramedf2+-------------+--------+ | Column Name | Type | +-------------+--------+ | student_id | int | | name | object | | age | int | +-------------+--------+
Write a solution to concatenate these two DataFrames vertically into one DataFrame.
The result format is in the following example.
Example 1:
Input: df1 +------------+---------+-----+ | student_id | name | age | +------------+---------+-----+ | 1 | Mason | 8 | | 2 | Ava | 6 | | 3 | Taylor | 15 | | 4 | Georgia | 17 | +------------+---------+-----+ df2 +------------+------+-----+ | student_id | name | age | +------------+------+-----+ | 5 | Leo | 7 | | 6 | Alex | 7 | +------------+------+-----+ Output: +------------+---------+-----+ | student_id | name | age | +------------+---------+-----+ | 1 | Mason | 8 | | 2 | Ava | 6 | | 3 | Taylor | 15 | | 4 | Georgia | 17 | | 5 | Leo | 7 | | 6 | Alex | 7 | +------------+---------+-----+ Explanation: The two DataFramess are stacked vertically, and their rows are combined.
Problem summary: DataFrame df1 +-------------+--------+ | Column Name | Type | +-------------+--------+ | student_id | int | | name | object | | age | int | +-------------+--------+ DataFrame df2 +-------------+--------+ | Column Name | Type | +-------------+--------+ | student_id | int | | name | object | | age | int | +-------------+--------+ Write a solution to concatenate these two DataFrames vertically into one DataFrame. The result format is in the following example.
Start with the most direct exhaustive search. That gives a correctness anchor before optimizing.
Pattern signal: General problem-solving
{"headers":{"df1":["student_id","name","age"],"df2":["student_id","name","age"]},"rows":{"df1":[[1,"Mason",8],[2,"Ava",6],[3,"Taylor",15],[4,"Georgia",17]],"df2":[[5,"Leo",7],[6,"Alex",7]]}}Source-backed implementations are provided below for direct study and interview prep.
// Accepted solution for LeetCode #2888: Reshape Data: Concatenate
// Auto-generated Java example from py.
class Solution {
public void exampleSolution() {
}
}
// Reference (py):
// # Accepted solution for LeetCode #2888: Reshape Data: Concatenate
// import pandas as pd
//
//
// def concatenateTables(df1: pd.DataFrame, df2: pd.DataFrame) -> pd.DataFrame:
// return pd.concat([df1, df2], ignore_index=True)
// Accepted solution for LeetCode #2888: Reshape Data: Concatenate
// Auto-generated Go example from py.
func exampleSolution() {
}
// Reference (py):
// # Accepted solution for LeetCode #2888: Reshape Data: Concatenate
// import pandas as pd
//
//
// def concatenateTables(df1: pd.DataFrame, df2: pd.DataFrame) -> pd.DataFrame:
// return pd.concat([df1, df2], ignore_index=True)
# Accepted solution for LeetCode #2888: Reshape Data: Concatenate
import pandas as pd
def concatenateTables(df1: pd.DataFrame, df2: pd.DataFrame) -> pd.DataFrame:
return pd.concat([df1, df2], ignore_index=True)
// Accepted solution for LeetCode #2888: Reshape Data: Concatenate
// Rust example auto-generated from py reference.
// Replace the signature and local types with the exact LeetCode harness for this problem.
impl Solution {
pub fn rust_example() {
// Port the logic from the reference block below.
}
}
// Reference (py):
// # Accepted solution for LeetCode #2888: Reshape Data: Concatenate
// import pandas as pd
//
//
// def concatenateTables(df1: pd.DataFrame, df2: pd.DataFrame) -> pd.DataFrame:
// return pd.concat([df1, df2], ignore_index=True)
// Accepted solution for LeetCode #2888: Reshape Data: Concatenate
// Auto-generated TypeScript example from py.
function exampleSolution(): void {
}
// Reference (py):
// # Accepted solution for LeetCode #2888: Reshape Data: Concatenate
// import pandas as pd
//
//
// def concatenateTables(df1: pd.DataFrame, df2: pd.DataFrame) -> pd.DataFrame:
// return pd.concat([df1, df2], ignore_index=True)
Use this to step through a reusable interview workflow for this problem.
Two nested loops check every pair or subarray. The outer loop fixes a starting point, the inner loop extends or searches. For n elements this gives up to n²/2 operations. No extra space, but the quadratic time is prohibitive for large inputs.
Most array problems have an O(n²) brute force (nested loops) and an O(n) optimal (single pass with clever state tracking). The key is identifying what information to maintain as you scan: a running max, a prefix sum, a hash map of seen values, or two pointers.
Review these before coding to avoid predictable interview regressions.
Wrong move: Loop endpoints miss first/last candidate.
Usually fails on: Fails on minimal arrays and exact-boundary answers.
Fix: Re-derive loops from inclusive/exclusive ranges before coding.