Off-by-one on range boundaries
Wrong move: Loop endpoints miss first/last candidate.
Usually fails on: Fails on minimal arrays and exact-boundary answers.
Fix: Re-derive loops from inclusive/exclusive ranges before coding.
Move from brute-force thinking to an efficient approach using core interview patterns strategy.
Table: Scores
+-------------+---------+ | Column Name | Type | +-------------+---------+ | id | int | | score | decimal | +-------------+---------+ id is the primary key (column with unique values) for this table. Each row of this table contains the score of a game. Score is a floating point value with two decimal places.
Write a solution to find the rank of the scores. The ranking should be calculated according to the following rules:
Return the result table ordered by score in descending order.
The result format is in the following example.
Example 1:
Input: Scores table: +----+-------+ | id | score | +----+-------+ | 1 | 3.50 | | 2 | 3.65 | | 3 | 4.00 | | 4 | 3.85 | | 5 | 4.00 | | 6 | 3.65 | +----+-------+ Output: +-------+------+ | score | rank | +-------+------+ | 4.00 | 1 | | 4.00 | 1 | | 3.85 | 2 | | 3.65 | 3 | | 3.65 | 3 | | 3.50 | 4 | +-------+------+
Problem summary: Table: Scores +-------------+---------+ | Column Name | Type | +-------------+---------+ | id | int | | score | decimal | +-------------+---------+ id is the primary key (column with unique values) for this table. Each row of this table contains the score of a game. Score is a floating point value with two decimal places. Write a solution to find the rank of the scores. The ranking should be calculated according to the following rules: The scores should be ranked from the highest to the lowest. If there is a tie between two scores, both should have the same ranking. After a tie, the next ranking number should be the next consecutive integer value. In other words, there should be no holes between ranks. Return the result table ordered by score in descending order. The result format is in the following example.
Start with the most direct exhaustive search. That gives a correctness anchor before optimizing.
Pattern signal: General problem-solving
{"headers": {"Scores": ["id", "score"]}, "rows": {"Scores": [[1, 3.50], [2, 3.65], [3, 4.00], [4, 3.85], [5, 4.00], [6, 3.65]]}}Source-backed implementations are provided below for direct study and interview prep.
// Accepted solution for LeetCode #178: Rank Scores
// Auto-generated Java example from py.
class Solution {
public void exampleSolution() {
}
}
// Reference (py):
// # Accepted solution for LeetCode #178: Rank Scores
// import pandas as pd
//
//
// def order_scores(scores: pd.DataFrame) -> pd.DataFrame:
// # Use the rank method to assign ranks to the scores in descending order with no gaps
// scores["rank"] = scores["score"].rank(method="dense", ascending=False)
//
// # Drop id column & Sort the DataFrame by score in descending order
// result_df = scores.drop("id", axis=1).sort_values(by="score", ascending=False)
//
// return result_df
// Accepted solution for LeetCode #178: Rank Scores
// Auto-generated Go example from py.
func exampleSolution() {
}
// Reference (py):
// # Accepted solution for LeetCode #178: Rank Scores
// import pandas as pd
//
//
// def order_scores(scores: pd.DataFrame) -> pd.DataFrame:
// # Use the rank method to assign ranks to the scores in descending order with no gaps
// scores["rank"] = scores["score"].rank(method="dense", ascending=False)
//
// # Drop id column & Sort the DataFrame by score in descending order
// result_df = scores.drop("id", axis=1).sort_values(by="score", ascending=False)
//
// return result_df
# Accepted solution for LeetCode #178: Rank Scores
import pandas as pd
def order_scores(scores: pd.DataFrame) -> pd.DataFrame:
# Use the rank method to assign ranks to the scores in descending order with no gaps
scores["rank"] = scores["score"].rank(method="dense", ascending=False)
# Drop id column & Sort the DataFrame by score in descending order
result_df = scores.drop("id", axis=1).sort_values(by="score", ascending=False)
return result_df
// Accepted solution for LeetCode #178: Rank Scores
// Rust example auto-generated from py reference.
// Replace the signature and local types with the exact LeetCode harness for this problem.
impl Solution {
pub fn rust_example() {
// Port the logic from the reference block below.
}
}
// Reference (py):
// # Accepted solution for LeetCode #178: Rank Scores
// import pandas as pd
//
//
// def order_scores(scores: pd.DataFrame) -> pd.DataFrame:
// # Use the rank method to assign ranks to the scores in descending order with no gaps
// scores["rank"] = scores["score"].rank(method="dense", ascending=False)
//
// # Drop id column & Sort the DataFrame by score in descending order
// result_df = scores.drop("id", axis=1).sort_values(by="score", ascending=False)
//
// return result_df
// Accepted solution for LeetCode #178: Rank Scores
// Auto-generated TypeScript example from py.
function exampleSolution(): void {
}
// Reference (py):
// # Accepted solution for LeetCode #178: Rank Scores
// import pandas as pd
//
//
// def order_scores(scores: pd.DataFrame) -> pd.DataFrame:
// # Use the rank method to assign ranks to the scores in descending order with no gaps
// scores["rank"] = scores["score"].rank(method="dense", ascending=False)
//
// # Drop id column & Sort the DataFrame by score in descending order
// result_df = scores.drop("id", axis=1).sort_values(by="score", ascending=False)
//
// return result_df
Use this to step through a reusable interview workflow for this problem.
Two nested loops check every pair or subarray. The outer loop fixes a starting point, the inner loop extends or searches. For n elements this gives up to n²/2 operations. No extra space, but the quadratic time is prohibitive for large inputs.
Most array problems have an O(n²) brute force (nested loops) and an O(n) optimal (single pass with clever state tracking). The key is identifying what information to maintain as you scan: a running max, a prefix sum, a hash map of seen values, or two pointers.
Review these before coding to avoid predictable interview regressions.
Wrong move: Loop endpoints miss first/last candidate.
Usually fails on: Fails on minimal arrays and exact-boundary answers.
Fix: Re-derive loops from inclusive/exclusive ranges before coding.