Off-by-one on range boundaries
Wrong move: Loop endpoints miss first/last candidate.
Usually fails on: Fails on minimal arrays and exact-boundary answers.
Fix: Re-derive loops from inclusive/exclusive ranges before coding.
Build confidence with an intuition-first walkthrough focused on core interview patterns fundamentals.
Table Activities:
+-------------+---------+ | Column Name | Type | +-------------+---------+ | sell_date | date | | product | varchar | +-------------+---------+ There is no primary key (column with unique values) for this table. It may contain duplicates. Each row of this table contains the product name and the date it was sold in a market.
Write a solution to find for each date the number of different products sold and their names.
The sold products names for each date should be sorted lexicographically.
Return the result table ordered by sell_date.
The result format is in the following example.
Example 1:
Input: Activities table: +------------+------------+ | sell_date | product | +------------+------------+ | 2020-05-30 | Headphone | | 2020-06-01 | Pencil | | 2020-06-02 | Mask | | 2020-05-30 | Basketball | | 2020-06-01 | Bible | | 2020-06-02 | Mask | | 2020-05-30 | T-Shirt | +------------+------------+ Output: +------------+----------+------------------------------+ | sell_date | num_sold | products | +------------+----------+------------------------------+ | 2020-05-30 | 3 | Basketball,Headphone,T-shirt | | 2020-06-01 | 2 | Bible,Pencil | | 2020-06-02 | 1 | Mask | +------------+----------+------------------------------+ Explanation: For 2020-05-30, Sold items were (Headphone, Basketball, T-shirt), we sort them lexicographically and separate them by a comma. For 2020-06-01, Sold items were (Pencil, Bible), we sort them lexicographically and separate them by a comma. For 2020-06-02, the Sold item is (Mask), we just return it.
Problem summary: Table Activities: +-------------+---------+ | Column Name | Type | +-------------+---------+ | sell_date | date | | product | varchar | +-------------+---------+ There is no primary key (column with unique values) for this table. It may contain duplicates. Each row of this table contains the product name and the date it was sold in a market. Write a solution to find for each date the number of different products sold and their names. The sold products names for each date should be sorted lexicographically. Return the result table ordered by sell_date. The result format is in the following example.
Start with the most direct exhaustive search. That gives a correctness anchor before optimizing.
Pattern signal: General problem-solving
{"headers":{"Activities":["sell_date","product"]},"rows":{"Activities":[["2020-05-30","Headphone"],["2020-06-01","Pencil"],["2020-06-02","Mask"],["2020-05-30","Basketball"],["2020-06-01","Bible"],["2020-06-02","Mask"],["2020-05-30","T-Shirt"]]}}finding-the-topic-of-each-post)Source-backed implementations are provided below for direct study and interview prep.
// Accepted solution for LeetCode #1484: Group Sold Products By The Date
// Auto-generated Java example from rust.
class Solution {
public void exampleSolution() {
}
}
// Reference (rust):
// // Accepted solution for LeetCode #1484: Group Sold Products By The Date
// pub fn sql_example() -> &'static str {
// r#"
// -- Accepted solution for LeetCode #1484: Group Sold Products By The Date
// SELECT
// sell_date,
// COUNT(DISTINCT product) AS num_sold,
// GROUP_CONCAT(DISTINCT product) AS products
// FROM Activities
// GROUP BY sell_date
// ORDER BY sell_date;
// "#
// }
// Accepted solution for LeetCode #1484: Group Sold Products By The Date
// Auto-generated Go example from rust.
func exampleSolution() {
}
// Reference (rust):
// // Accepted solution for LeetCode #1484: Group Sold Products By The Date
// pub fn sql_example() -> &'static str {
// r#"
// -- Accepted solution for LeetCode #1484: Group Sold Products By The Date
// SELECT
// sell_date,
// COUNT(DISTINCT product) AS num_sold,
// GROUP_CONCAT(DISTINCT product) AS products
// FROM Activities
// GROUP BY sell_date
// ORDER BY sell_date;
// "#
// }
# Accepted solution for LeetCode #1484: Group Sold Products By The Date
# Auto-generated Python example from rust.
def example_solution() -> None:
return
# Reference (rust):
# // Accepted solution for LeetCode #1484: Group Sold Products By The Date
# pub fn sql_example() -> &'static str {
# r#"
# -- Accepted solution for LeetCode #1484: Group Sold Products By The Date
# SELECT
# sell_date,
# COUNT(DISTINCT product) AS num_sold,
# GROUP_CONCAT(DISTINCT product) AS products
# FROM Activities
# GROUP BY sell_date
# ORDER BY sell_date;
# "#
# }
// Accepted solution for LeetCode #1484: Group Sold Products By The Date
pub fn sql_example() -> &'static str {
r#"
-- Accepted solution for LeetCode #1484: Group Sold Products By The Date
SELECT
sell_date,
COUNT(DISTINCT product) AS num_sold,
GROUP_CONCAT(DISTINCT product) AS products
FROM Activities
GROUP BY sell_date
ORDER BY sell_date;
"#
}
// Accepted solution for LeetCode #1484: Group Sold Products By The Date
// Auto-generated TypeScript example from rust.
function exampleSolution(): void {
}
// Reference (rust):
// // Accepted solution for LeetCode #1484: Group Sold Products By The Date
// pub fn sql_example() -> &'static str {
// r#"
// -- Accepted solution for LeetCode #1484: Group Sold Products By The Date
// SELECT
// sell_date,
// COUNT(DISTINCT product) AS num_sold,
// GROUP_CONCAT(DISTINCT product) AS products
// FROM Activities
// GROUP BY sell_date
// ORDER BY sell_date;
// "#
// }
Use this to step through a reusable interview workflow for this problem.
Two nested loops check every pair or subarray. The outer loop fixes a starting point, the inner loop extends or searches. For n elements this gives up to n²/2 operations. No extra space, but the quadratic time is prohibitive for large inputs.
Most array problems have an O(n²) brute force (nested loops) and an O(n) optimal (single pass with clever state tracking). The key is identifying what information to maintain as you scan: a running max, a prefix sum, a hash map of seen values, or two pointers.
Review these before coding to avoid predictable interview regressions.
Wrong move: Loop endpoints miss first/last candidate.
Usually fails on: Fails on minimal arrays and exact-boundary answers.
Fix: Re-derive loops from inclusive/exclusive ranges before coding.